WORLDBASE Game / Partie #1214143
[Event "35th Panam Youth U18 2025"]
[Site "Lima PER"]
[Date "2025.07.30"]
[Round "4.2"]
[White "Cherukuri, Nitesh"]
[Black "Venkatesh, Narayan"]
[Result "1/2-1/2"]
[WhiteElo "2233"]
[BlackElo "2185"]
[ECO "C46"]
[PlyCount "125"]

1.e4 e5 2.Nf3 Nc6 3.Nc3 Nf6 4.a3 d5 5.Bb5 d4 6.Ne2 Bd6 7.d3 O-O 8.O-O Ne7 9.Bc4 c5 10.Ng3 a6 11.a4 Rb8 12.a5 Nc6 13.Bd2 Bc7 14.Qe1 Ne8 15.Kh1 Kh8 16.Bg5 f6 17.Bd2 Nd6 18.Bb3 Bd7 19.Nh4 Ne7 20.f4 Bb5 21.fxe5 fxe5 22.Qe2 Qd7 23.Bg5 Ng6 24.Nxg6+ hxg6 25.h4 Rbe8 26.h5 Bd8 27.Rxf8+ Rxf8 28.Rf1 Rxf1+ 29.Qxf1 Qe8 30.Bxd8 Qxd8 31.hxg6 Qf6 32.Qxf6 gxf6 33.Bd5 Bc6 34.Bxc6 bxc6 35.Nf5 Nb7 36.Kh2 c4 37.Kg3 cxd3 38.cxd3 Nc5 39.g7+ Kh7 40.Ne7 Kxg7 41.Nxc6 Nxd3 42.b4 Kf7 43.b5 Nc5 44.Nb4 axb5 45.a6 Nxa6 46.Nxa6 Kg6 47.Kg4 d3 48.Kf3 f5 49.Nc5 d2 50.Ke2 Kg5 51.exf5 Kxf5 52.Kxd2 Kf4 53.Ke2 e4 54.Kf2 e3+ 55.Kf1 b4 56.Nb3 Kg3 57.Nd4 b3 58.Ne2+ Kg4 59.Ke1 b2 60.Nc3 Kg3 61.Ke2 Kxg2 62.Kxe3 b1=Q 63.Nxb1 1/2-1/2
[Event "35th Panam Youth U18 2025"] [Site "Lima PER"] [Date "2025.07.30"] [Round "4.2"] [White "Cherukuri, Nitesh"] [Black "Venkatesh, Narayan"] [Result "1/2-1/2"] [WhiteTitle "CM"] [BlackTitle "FM"] [WhiteElo "2233"] [BlackElo "2185"] [ECO "C46"] [Opening "Four knights"] [Variation "Gunsberg variation"] [EventDate "2025.07.28"] [WhiteFideId "30978688"] [BlackFideId "30987881"] 1. e4 e5 2. Nf3 Nc6 3. Nc3 Nf6 4. a3 d5 5. Bb5 d4 6. Ne2 Bd6 7. d3 O-O 8. O-O Ne7 9. Bc4 c5 10. Ng3 a6 11. a4 Rb8 12. a5 Nc6 13. Bd2 Bc7 14. Qe1 Ne8 15. Kh1 Kh8 16. Bg5 f6 17. Bd2 Nd6 18. Bb3 Bd7 19. Nh4 Ne7 20. f4 Bb5 21. fxe5 fxe5 22. Qe2 Qd7 23. Bg5 Ng6 24. Nxg6+ hxg6 25. h4 Rbe8 26. h5 Bd8 27. Rxf8+ Rxf8 28. Rf1 Rxf1+ 29. Qxf1 Qe8 30. Bxd8 Qxd8 31. hxg6 Qf6 32. Qxf6 gxf6 33. Bd5 Bc6 34. Bxc6 bxc6 35. Nf5 Nb7 36. Kh2 c4 37. Kg3 cxd3 38. cxd3 Nc5 39. g7+ Kh7 40. Ne7 Kxg7 41. Nxc6 Nxd3 42. b4 Kf7 43. b5 Nc5 44. Nb4 axb5 45. a6 Nxa6 46. Nxa6 Kg6 47. Kg4 d3 48. Kf3 f5 49. Nc5 d2 50. Ke2 Kg5 51. exf5 Kxf5 52. Kxd2 Kf4 53. Ke2 e4 54. Kf2 e3+ 55. Kf1 b4 56. Nb3 Kg3 57. Nd4 b3 58. Ne2+ Kg4 59. Ke1 b2 60. Nc3 Kg3 61. Ke2 Kxg2 62. Kxe3 b1=Q 63. Nxb1 1/2-1/2