WORLDBASE Game / Partie #871890
[Event "9th Oviedo Open 2023"]
[Site "Oviedo ESP"]
[Date "2023.07.29"]
[Round "8.6"]
[White "Lianes Garcia, Marcos"]
[Black "Lopez Varela, Pablo"]
[Result "0-1"]
[WhiteElo "2407"]
[BlackElo "2300"]
[ECO "B48"]
[PlyCount "123"]

1.e4 c5 2.Nf3 e6 3.d4 cxd4 4.Nxd4 Nc6 5.Nc3 Qc7 6.Be3 a6 7.Qf3 Nf6 8.O-O-O Ne5 9.Qg3 b5 10.f4 Neg4 11.Bg1 h5 12.e5 b4 13.Na4 Ne4 14.Qe1 Bb7 15.h3 Nh6 16.Bd3 Nc5 17.Nxc5 Bxc5 18.Rh2 Rc8 19.g4 Ng8 20.Nb3 Bxg1 21.Qxg1 Kf8 22.gxh5 Rxh5 23.Qg4 g6 24.f5 exf5 25.Qxb4+ Ne7 26.Re1 Ke8 27.Kb1 Nd5 28.Qd2 f4 29.Na5 Ne3 30.Nxb7 Qxb7 31.Rf2 g5 32.Qa5 Rxh3 33.e6 dxe6 34.Qxg5 Rb8 35.b3 Nd5 36.Bc4 Qb4 37.Qe5 Ne3 38.Rxe3 Rxe3 39.Qxf4 Re1+ 40.Kb2 Rb7 41.Rh2 Qa5 42.Rh8+ Ke7 43.Qh4+ Kd7 44.Rh5 Qd2 45.Rh8 Qc1+ 46.Kc3 Re3+ 47.Bd3 Rc7+ 48.Kb4 Qe1+ 49.Qxe1 Rxe1 50.Bxa6 Rxc2 51.a4 Re4+ 52.Bc4 f5 53.a5 Ra2 54.Ra8 f4 55.Kc5 f3 56.a6 Ke7 57.Rh8 f2 58.Rh7+ Kf6 59.Rh1 Re1 60.Rh6+ Kg7 61.Rh3 f1=Q 62.Kd4 0-1
[Event "9th Oviedo Open 2023"] [Site "Oviedo ESP"] [Date "2023.07.29"] [Round "8.6"] [White "Lianes Garcia, Marcos"] [Black "Lopez Varela, Pablo"] [Result "0-1"] [WhiteTitle "IM"] [BlackTitle "FM"] [WhiteElo "2407"] [BlackElo "2300"] [ECO "B48"] [Opening "Sicilian"] [Variation "Taimanov variation"] [EventDate "2023.07.24"] [WhiteFideId "32060777"] [BlackFideId "32092105"] 1. e4 c5 2. Nf3 e6 3. d4 cxd4 4. Nxd4 Nc6 5. Nc3 Qc7 6. Be3 a6 7. Qf3 Nf6 8. O-O-O Ne5 9. Qg3 b5 10. f4 Neg4 11. Bg1 h5 12. e5 b4 13. Na4 Ne4 14. Qe1 Bb7 15. h3 Nh6 16. Bd3 Nc5 17. Nxc5 Bxc5 18. Rh2 Rc8 19. g4 Ng8 20. Nb3 Bxg1 21. Qxg1 Kf8 22. gxh5 Rxh5 23. Qg4 g6 24. f5 exf5 25. Qxb4+ Ne7 26. Re1 Ke8 27. Kb1 Nd5 28. Qd2 f4 29. Na5 Ne3 30. Nxb7 Qxb7 31. Rf2 g5 32. Qa5 Rxh3 33. e6 dxe6 34. Qxg5 Rb8 35. b3 Nd5 36. Bc4 Qb4 37. Qe5 Ne3 38. Rxe3 Rxe3 39. Qxf4 Re1+ 40. Kb2 Rb7 41. Rh2 Qa5 42. Rh8+ Ke7 43. Qh4+ Kd7 44. Rh5 Qd2 45. Rh8 Qc1+ 46. Kc3 Re3+ 47. Bd3 Rc7+ 48. Kb4 Qe1+ 49. Qxe1 Rxe1 50. Bxa6 Rxc2 51. a4 Re4+ 52. Bc4 f5 53. a5 Ra2 54. Ra8 f4 55. Kc5 f3 56. a6 Ke7 57. Rh8 f2 58. Rh7+ Kf6 59. Rh1 Re1 60. Rh6+ Kg7 61. Rh3 f1=Q 62. Kd4 0-1